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Titlebook: Counterexamples in Operator Theory; Mohammed Hichem Mortad Textbook 2022 The Editor(s) (if applicable) and The Author(s), under exclusive

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31#
發(fā)表于 2025-3-26 23:14:14 | 只看該作者
(Square) Roots of Bounded OperatorsLet .?∈?.(.). We say that .?∈?.(.) is a square root of . if ..?=?..
32#
發(fā)表于 2025-3-27 01:59:52 | 只看該作者
33#
發(fā)表于 2025-3-27 06:39:48 | 只看該作者
SpectrumLet .?∈?.(.) where . is a complex Hilbert space. The set . is called the spectrum of ..
34#
發(fā)表于 2025-3-27 10:26:30 | 只看該作者
Spectral Radius, Numerical RangeLet . be in .(.). The spectral radius of . is defined as
35#
發(fā)表于 2025-3-27 14:09:24 | 只看該作者
Functional CalculiThe functional calculus aims to define .(.) where . is a fixed operator, and . belongs to some classes of functions defined in domains containing .(.), say. We already know that this is possible for any polynomial .. We also know how to define the exponential of . at an undergraduate level (this will be recalled in Chap. .).
36#
發(fā)表于 2025-3-27 21:46:12 | 只看該作者
37#
發(fā)表于 2025-3-27 23:17:32 | 只看該作者
38#
發(fā)表于 2025-3-28 05:56:46 | 只看該作者
Similarity and Unitary EquivalenceClearly, . and . have the same eigenvalues which, in this setting, means that . and . have equal spectra. To see why . and . are not unitarily equivalent, remember that two unitarily equivalent operators are simultaneously (e.g.) self-adjoint. Since . is self-adjoint and . is not, it follows that they cannot be unitarily equivalent.
39#
發(fā)表于 2025-3-28 08:06:15 | 只看該作者
The Sylvester EquationConsider the operator equation: . where ., ., .?∈?.(.) are given and .?∈?.(.) is the unknown. This equation is more commonly known as the Sylvester equation.
40#
發(fā)表于 2025-3-28 11:29:58 | 只看該作者
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