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Titlebook: Cardinal Functions on Boolean Algebras; J. Donald Monk Book 1990 Springer Basel AG 1990 algebra.Boolean algebra.cardinal function.function

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樓主
發(fā)表于 2025-3-21 19:16:31 | 只看該作者 |倒序?yàn)g覽 |閱讀模式
書目名稱Cardinal Functions on Boolean Algebras
編輯J. Donald Monk
視頻videohttp://file.papertrans.cn/222/221847/221847.mp4
叢書名稱Lectures in Mathematics. ETH Zürich
圖書封面Titlebook: Cardinal Functions on Boolean Algebras;  J. Donald Monk Book 1990 Springer Basel AG 1990 algebra.Boolean algebra.cardinal function.function
出版日期Book 1990
關(guān)鍵詞algebra; Boolean algebra; cardinal function; function; functions
版次1
doihttps://doi.org/10.1007/978-3-0348-6381-0
isbn_softcover978-3-7643-2495-7
isbn_ebook978-3-0348-6381-0
copyrightSpringer Basel AG 1990
The information of publication is updating

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沙發(fā)
發(fā)表于 2025-3-21 22:09:07 | 只看該作者
板凳
發(fā)表于 2025-3-22 01:22:36 | 只看該作者
Cardinality,.. = 2. for A satisfying CSP. W. Just [88] has shown that it is consistent to have a BA . such that ω. ≤ Card.. = |.| < 2ω. Questions about Card. are connected to some problems about cofinality and related cardinal functions which will not be considered here; see van Douwen [89]. The cardinal function Card. is defined as follows:
地板
發(fā)表于 2025-3-22 05:46:15 | 只看該作者
Character,. ∈ . and ... = 0 for . ? .. Then . is the set of all.such that .. ≤ . for some cofinite subset . of .. So, it is clear that . ≤ .|. If . is a set of generators for . with |.| < |.|, then there is a . ∈ . such that . ? .. for infinitely many cofinite subsets . of .; this is clearly impossible.
5#
發(fā)表于 2025-3-22 10:20:51 | 只看該作者
6#
發(fā)表于 2025-3-22 15:08:58 | 只看該作者
7#
發(fā)表于 2025-3-22 17:35:17 | 只看該作者
https://doi.org/10.1007/978-981-99-7879-3of . such that . ? .. But it is a very elementary exercise to show that no ultrafilter is included in a finite union of other, different, ultrafilters. So, t. ≥ ., and hence t. ≥ . for every infinite BA ..
8#
發(fā)表于 2025-3-22 23:15:27 | 只看該作者
,-Weight, . with π . < π ., and if we take . = . and . = ./Fin, then π . = ω; while π . = 2. since A has a disjoint subset of size 2.. Turning to products, we have (math) for any system (.. : . ∈ .) of infinite BA’s. For, ≥ is clear; now suppose .. is a dense subset of .. for each . ∈ ..
9#
發(fā)表于 2025-3-23 03:51:30 | 只看該作者
10#
發(fā)表于 2025-3-23 07:29:28 | 只看該作者
Tightness,of . such that . ? .. But it is a very elementary exercise to show that no ultrafilter is included in a finite union of other, different, ultrafilters. So, t. ≥ ., and hence t. ≥ . for every infinite BA ..
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