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Titlebook: Generalized Functions Theory and Technique; Theory and Technique Ram P. Kanwal Book 19982nd edition Birkh?user Boston 1998 Boundary value p

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11#
發(fā)表于 2025-3-23 11:16:26 | 只看該作者
12#
發(fā)表于 2025-3-23 15:24:19 | 只看該作者
https://doi.org/10.1007/978-3-319-44577-9mptotic evaluation of divergent integrals, boundary layer theory and singular perturbations. Our aim in this chapter is to present the basic concepts of their methods and illustrate them with representative examples.
13#
發(fā)表于 2025-3-23 20:19:20 | 只看該作者
14#
發(fā)表于 2025-3-23 23:50:31 | 只看該作者
15#
發(fā)表于 2025-3-24 04:49:57 | 只看該作者
16#
發(fā)表于 2025-3-24 10:19:35 | 只看該作者
17#
發(fā)表于 2025-3-24 14:44:39 | 只看該作者
Congenital Pseudarthrosis of the Clavicleproduct of the distributions .(.) ∈ .′. and .(.) ∈ .′. according to (1),.and check whether the right side of this equation defines a linear continuous functional over .. For this purpose, we prove the following lemma:.(.) = <.(.), .(.)>, . ∈ .′.(.) ∈ ., ., . (., .,..., .) . {.(.)} → .(.) . → ∞, .(.) = {<.(.), .(.)>} → .(.) . → ∞.
18#
發(fā)表于 2025-3-24 17:42:51 | 只看該作者
Direct Products and Convolutions of Distributions,product of the distributions .(.) ∈ .′. and .(.) ∈ .′. according to (1),.and check whether the right side of this equation defines a linear continuous functional over .. For this purpose, we prove the following lemma:.(.) = <.(.), .(.)>, . ∈ .′.(.) ∈ ., ., . (., .,..., .) . {.(.)} → .(.) . → ∞, .(.) = {<.(.), .(.)>} → .(.) . → ∞.
19#
發(fā)表于 2025-3-24 19:54:27 | 只看該作者
Applications to Wave Propagation,ul method of attacking these problems is to embed them in the whole space. This is achieved by extending the solution to the other side of the surface in some suitable fashion, as we did in deriving the Poisson integral formula in Chapter 10. We then obtain a regular singular function that satisfies
20#
發(fā)表于 2025-3-25 01:14:07 | 只看該作者
https://doi.org/10.1007/978-1-4613-8315-4ul method of attacking these problems is to embed them in the whole space. This is achieved by extending the solution to the other side of the surface in some suitable fashion, as we did in deriving the Poisson integral formula in Chapter 10. We then obtain a regular singular function that satisfies
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