Titlebook: Calculus Made Easy; Silvanus P. Thompson,Martin Gardner Textbook Nov 1999Latest edition Macmillan Publishers Limited 1998

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Partial Fractions and Inverse Functions the result is bound to be a complicated expression. If we could split the fraction into two or more simpler fractions such that their sum is equivalent to the original fraction, we could then proceed by differentiating each of these simpler expressions. And the result of differentiating would be th

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Textbook Nov 1999Latest editionters, and added more than 20 recreational problems for practice and enjoyment. He has transformed this classic primer into a modern masterpiece that explains the timeless concepts of calculus in a contemporary and user-friendly voice.

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https://doi.org/10.1007/978-3-030-63820-7e sum of two (or more) derivatives, each one of which is relatively simple; while the final expression, though of course it will be the same as that which could be obtained without resorting to this dodge, is thus obtained with much less effort and appears in a simplified form.